48÷2(9+3) = ????
- Thread starter nubian
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LOL
this is EXACTLY why we use brackets and parentheses ...
a/bc = a/(bc)
if the problem was presented like this "a/bc" without brackets you could play devil's advocate and argue OP .... but it is not the brackets join the two functions 2*(9+3) into ONE
fam just stop
Written exactly like this its clear. But, that is where the debate lays.
Last edited:
I knew you didn't read the shit. You are using a bunch of words here, that you have no idea about their meaning. Let's start off with the small word, "shortcut". How the fuck, is adding the 9 to the 3 first, a shortcut? You deliberately saying that this is not right to do shows you don't know the first step of the order of operations.
Explain your reasoning for using "Null Value" in your discussion. Google that shit futhafucka and see if it means what you thought it meant.
Do the same shit for converge.
Gonna throw some asterisks below this one to point it out later. **************************************************
Because this is hard work hu?
Gonna throw some asterisks below this one to point it out later. **************************************************
You are the honest mistake.
Pointing out now
**************************************************
Bingo you dumbass, which is why your stupid ass should understand that adding the 9 and the 3 is not a shortcut, but FOCUSING on what is in the parenthesis.
You can't make dumbness up this bad.
(5+3)^2 solved without taking shortcuts
(5+3)(5+3)= 25+15+15+9= 64
treks example has the problem being solved in this manner
(5+3)^2 = (8)^2=64
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Pause!
How the fuck is this taking a shortcut. Your brain is a shortcut. These are not binomials, they are two integers added together and squared inside of ()'s.
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now, if you agree that there is a binomial there, than you must recall that binomials are solved in this manner when raised to a power. i'll square in my example. the process works the same no matter what power you raise the -nomial.
(a+b)^2 = (a+b)(a+b)= a^2+2ab+b^2
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Pause again,
this formula is useful when you do have binomial, it's useless here.
Do you really think it's the same formula for higher order exponents?
Basically you are saying that like...
(a+b)^2 = (a+b)(a+b)= a^2+2ab+b^2
(a+b)^3 = (a+b)(a+b)= a^3+3ab+b^3
(a+b)^4 = (a+b)(a+b)= a^4+4ab+b^4
It doesn't work like that you ignorant fuck! More like this...
Even still, it's useless information because the 9 and the 3 are just integers. Just add them bitch.
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You see why now? Dummy!
I just added you and the moon!
you are one stupid fuck
here is what (a+b)^3 looks like without shortcuts you bumbling dumbass. if you could follow simple patterns you'd know this,
anyway, here we go for your ignorant ass:
(a + b)^3=
(a + b)(a + b)(a + b)=
((a + b)(a + b))(a + b)=
(a^2 + ab + ab + b^2)(a + b)=
(a^3+ a^2b + a^2b + ab^2 + a^2b + ab^2 + ab^2 + b^3)
combine like terms after multiplying through
a^3 + 3a^2b + 3ab^2 + b^3 - voila!
you're a real fucktard you know that?
I have a very clear understanding of it, sir. You're trying to recreate basic math to make yourself right. It doesn't work that way fam.
Add another to the list of people who dont understand the order of ops.
The above equation is unequivocally false.
You won't find a calculator, software, etc. in the world that tells you
10/5*2=1
They'll all say,
10/5*2=4
Just admit you misunderstood the order of ops.
Correct.
Provide facts dude. You can say its false all day, and it doesnt mean shit..
I just ran it on Mathway, and got this...
Dispute it with a source and FACTS.
you can make the statement true if you set the values for a b c like this
a= i
b= -1
c= 1
so no, it's not unequivocally false
I shitted on this video 12 ways from Sunday, as far as it's relation to the OP's problem.
You aren't understanding. You are doing the multiplication first thinking it's the implied multiplication taking precedent, but it is simply the multiplication taking precedent over the subtraction.
When you introduce division ahead of the multiplication you then solve the equation from left to right, as division takes precedence over multiplication - which includes both implicit and explicit multiplication.
To the others, I suggest you just ignore nathan.
Let's let followup realize the error of her ways.
this is all you need to know ... I provided the example using quarters on page 27 lol ... should have killed the confusion there because it shows you can't do it in the order you guys are trying to do it
Written that way i would get 288
Left to right rule. With the bracket, I however disagree
My calculator and source material have it the other way though....
/thread
well I think it's great that they have someone there to answer so quickly, but the software flaw is one that should be an easy fix. as long as they put in that the parentheses supercede all other operations, the flaw would be fixed...
Are these not your words buddy. Ain't it still pointless when they are integers.
Just add them up bitch.
But like you say, adding them up, is harder to do than remembering the formulas for binomial expansion though right?
That's not what they are useful for.
Just add them up bitch.
Integers and scalars are the same thing, don't panic.
Now just add them up bitch.
OH AND NIGGA, YOU WERE ON THAT WAGON.
Now go add them up bitch!
Totally different problem. Their aren't any Parentheses that would have to be Simplified first.
If the equation was..
10÷5(2)
It would then equal 1.
Oh, look guys, another red herring.
Let's make a, b, c real numbers since that's all we've been dealing with to this point.
Now, do YOU care to answer the question?
so now you're going to have 2 divided by 586 because you are grouping 48 with 9+3 which means you have to multiply 48 through the grouping or shortcut and add then multiply? you didn't do that at first though. can you explain why that is?
LS. Why would implicit multiplication take precedence over multiplication.
When you simplify the parentheses you can essentially remove it.
It is ONLY what is within the parentheses. Since (2)(12) functions as another manner of writing 2*12 or 2x12.
You start fucking with math when you flip rules and get confused by the parentheses and implicit multiplication. People are getting confused because of the lack of space between the 2(12).
They are simply DRAWN to solving it first by virtue of it APPEARING together.
Wow. You're serious too which is really scary.. Multiplication whether its implied on not takes precedent over Subtraction. Its called Simplification and it was explained to you thoroughly in that video. You're just attempting to discredit it because it destroys your argument.
Are these not your words buddy. Ain't it still pointless when they are integers.
Just add them up bitch.
But like you say, adding them up, is harder to do than remembering the formulas for binomial expansion though right?
That's not what they are useful for.
Just add them up bitch.
Integers and scalars are the same thing, don't panic.
Now just add them up bitch.
OH AND NIGGA, YOU WERE ON THAT WAGON.
Now go add them up bitch!
i was laughing at @hole sonning himself because that's the only party that i was engaged with at the time. now, go pull up the earlier post where i expressly stated the two terms meant the same thing you simple assed one trick pony
Ok my last time trying to break it down
if you have a 100 dollar bill and you are looking to find out how many $10 bills you can get change for??
would the equation not be
100÷10
or
100÷(5+5)
or
100÷2(5)??
how much is that??
100÷2 x 5 = 50 x 5 = Two Hundred and Twenty Five $10 bills?
or
100÷(2x5) = 100÷10 = ten $10 Bills?
Which one is it?
stop being stubborn and prideful and use your damn common sense
or show me how your equation can work using REAL WORLD applications like money, apples, whatever
BGOL Let's delete this thread and never speak of it again
if you have a 100 dollar bill and you are looking to find out how many $10 bills you can get change for??
would the equation not be
100÷10
or
100÷(5+5)
or
100÷2(5)??
how much is that??
100÷2 x 5 = 50 x 5 = Two Hundred and Twenty Five $10 bills?
or
100÷(2x5) = 100÷10 = ten $10 Bills?
Which one is it?
stop being stubborn and prideful and use your damn common sense
or show me how your equation can work using REAL WORLD applications like money, apples, whatever
BGOL Let's delete this thread and never speak of it again
so now you're going to have 2 divided by 586 because you are grouping 48 with 9+3 which means you have to multiply 48 through the grouping or shortcut and add then multiply? you didn't do that at first though. can you explain why that is?
Look up dude, i'm not gonna repeat myself a million times.
That reciprocal argument was weak to begin with cuz it never addressed the point of dispute which is the direct multi-line version of this single line problem.
I see what you are doing.Wow. You're serious too which is really scary.. Multiplication whether its implied on not takes precedent over Subtraction. Its called Simplification and it was explained to you thoroughly in that video. You're just attempting to discredit it because it destroys your argument.
What I said was the video is correct, but your insistence that it bears any relation to the problem at hand is incorrect.
Hence the "in relation to the OP's problem."
It is beyond clear that you are simply too dense to understand what is going on.
Of course it takes precedence over subtraction. I said as much in that very post you quoted, yet you are trying to act like I am saying the opposite - despite saying clearly
I do see there is a point of confusion in my post.
I said
I meant that to be division takes precedent over multiplication when it appears to the left of multiplication.
ex
4 / 2 * 6
division first, multiplication second.
I am not discrediting the video, but your application of it as proof of you doing the 2(12) first under ANY circumstance.
Where we not discussing this problem?
10/5*2
Im obviously starting to believe you're just being a pessimist.
But even in that problem, the bc constitutes multiplication which is the 3rd letter in PEMDAS. Whether there are Parentheses there is beside the point.
bump for the typing monkey with the dog's name
I knew you didn't read the shit. You are using a bunch of words here, that you have no idea about their meaning. Let's start off with the small word, "shortcut". How the fuck, is adding the 9 to the 3 first, a shortcut? You deliberately saying that this is not right to do shows you don't know the first step of the order of operations.
Explain your reasoning for using "Null Value" in your discussion. Google that shit futhafucka and see if it means what you thought it meant.
Do the same shit for converge.
Gonna throw some asterisks below this one to point it out later. **************************************************
Because this is hard work hu?
Gonna throw some asterisks below this one to point it out later. **************************************************
You are the honest mistake.
Pointing out now
**************************************************
Bingo you dumbass, which is why your stupid ass should understand that adding the 9 and the 3 is not a shortcut, but FOCUSING on what is in the parenthesis.
You can't make dumbness up this bad.
you are one stupid fuck
here is what (a+b)^3 looks like without shortcuts you bumbling dumbass. if you could follow simple patterns you'd know this,
anyway, here we go for your ignorant ass:
(a + b)^3=
(a + b)(a + b)(a + b)=
((a + b)(a + b))(a + b)=
(a^2 + ab + ab + b^2)(a + b)=
(a^3+ a^2b + a^2b + ab^2 + a^2b + ab^2 + ab^2 + b^3)
combine like terms after multiplying through
a^3 + 3a^2b + 3ab^2 + b^3 - voila!
you're a real fucktard you know that?
I understand
But
a(b+c) is the same as ac+ab
That is why i disagree even though they imply the same thing.
Ok my last time trying to break it down
if you have a 100 dollar bill and you are looking to find out how many $10 bills you can get change for??
would the equation not be
100÷10
or
100÷(5+5)
or
100÷2(5)??
Yes, yes No. The last equation should be 100/(2(5)).
Your examples are useless as they don't attempt to adress the point of dispute.
Where we not discussing this problem?
10/5*2
Im obviously starting to believe you're just being a pessimist.
But even in that problem, the bc constitutes multiplication which is the 3rd letter in PEMDAS. Whether there are Parentheses there is beside the point.
Exactly....there are no parentheses in that problem.
So for you to say
10/5*2=1
Means you DON'T understand PEMDAS.
Where we not discussing this problem?
10/5*2
Im obviously starting to believe you're just being a pessimist.
But even in that problem, the bc constitutes multiplication which is the 3rd letter in PEMDAS. Whether there are Parentheses there is beside the point.
errrrr, can't roll with you on that lsat point buddy.
I see what you're saying, but the division doesn't take precedent. You always Simplify first.
I knew you didn't read the shit. You are using a bunch of words here, that you have no idea about their meaning. Let's start off with the small word, "shortcut". How the fuck, is adding the 9 to the 3 first, a shortcut? You deliberately saying that this is not right to do shows you don't know the first step of the order of operations.
Explain your reasoning for using "Null Value" in your discussion. Google that shit futhafucka and see if it means what you thought it meant.
Do the same shit for converge.
Gonna throw some asterisks below this one to point it out later. **************************************************
Because this is hard work hu?
Gonna throw some asterisks below this one to point it out later. **************************************************
You are the honest mistake.
Pointing out now
**************************************************
Bingo you dumbass, which is why your stupid ass should understand that adding the 9 and the 3 is not a shortcut, but FOCUSING on what is in the parenthesis.
You can't make dumbness up this bad.
you are one stupid fuck
here is what (a+b)^3 looks like without shortcuts you bumbling dumbass. if you could follow simple patterns you'd know this,
anyway, here we go for your ignorant ass:
(a + b)^3=
(a + b)(a + b)(a + b)=
((a + b)(a + b))(a + b)=
(a^2 + ab + ab + b^2)(a + b)=
(a^3+ a^2b + a^2b + ab^2 + a^2b + ab^2 + ab^2 + b^3)
combine like terms after multiplying through
a^3 + 3a^2b + 3ab^2 + b^3 - voila!
you're a real fucktard you know that?
You can say what the fuck you want.
You went from here, (a + b)^3=
to here, (a^3+ a^2b + a^2b + ab^2 + a^2b + ab^2 + ab^2 + b^3, in your second order example and implied it was the same for higher orders by saying it was the same.
When you speak, I expect the worst, I can't give you the benefit of the doubt anymore.
I didn't make that shit up. That is what you wrote. I know how to derive the expansion formulas, but more importantly, I know when I need to use them and when I don't.
You keep bringing your useless information in here.
Just add the 9 and 3 up bitch!
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