48÷2(9+3) = ????

[Gods_Debris]

As has been explained to you several times, "parentheses" step refers to what's inside of the parentheses. Everything inside has to be resolved down to a single number (by performing a secondary PEMDAS loop) before moving on to the next level.


PS

2(a+b) =2*(a+b) = 2a + 2b

That's the distributive property. You skip the middle step because it is implied, and that's fine, but it's there.

does the distributive property come first or second in the equation you just 'helped' me to solve


you are PRESUMING 48 halfs while I am taking the literal equation and solving as it is WRITTEN.


the highlighted portion bgol is the first place i've ever heard that ridiculous limtation place on the terms inside the marks so i invite you to show me a mathematical source that states that rule.

 

[Gods_Debris]

Negros crossing milestones today.

ok you can go back to fingerpainting now son.

and it's spelled negroEs with an 'e' son, practice that with your mom dukes before i get home cause i'm gonna quiz ya right after she cleans my feet makes my dinner and i wax that flat chalky black ass of hers. you can advise her as to these orders of operatin: whether she should take oral before or after she takes it up her ass. can't believe you kiss that brawd in her mouth

 

[Rawness]

does the distributive property come first or second in the equation you just 'helped' me to solve

My phone doesn't have the three horizontal lines symbol which; if you've dealt with math at any higher level, then you'd know it means "is defined as"....for the sake of this discussion I'll use double equal signs.

2(a+b )== 2*(a+b) = 2a + 2b

you are PRESUMING 48 halfs while I am taking the literal equation and solving as it is WRITTEN.

No, I'm making NO presumptions....that's the whole point of the PEMDAS convention being adapted centuries ago. Before being accepted what you're doing was just fine, HOWEVER, since it's adoption, you must follow the the convention.

Y'all added this distributive property angle to try to cloud your way into making the answer 2. Fact is, the distributive property is an alegbraic tool needed to carry variables.
You just solve in arithmetic, no need to distribute (you can distribute, mind you, but you keep butchering the interpretation), so just let the convention guide you through.

 

[mallorquin]

yeah, you're spending hours jumping on photoshop to make unfunny dry ass corn ball jokes for the mouth breathing crowd that only 5 people on earth and the internet will ever see all the while not contributing anything to the discussion but I'M the dummy? errrrr, okay run with that

Like I told you yesterday, you are doing this to yourself. I am not the only one who started posting gifs, and I can guarantee that, with soon to be 50 pages, a lot more than 5 people have seen your ignorance on display. You can call it corny if you want, this is bgol, this is what we do.
As far as me not contributing, I've surfaced to air missile'd your ass outta the sky several times since Saturday, by manipulating your ignorance.
Remember the 9+3 that can't be added before distributing (Even though it's in parenthesis) bullshit you said last night? I pulled this out of you.
Like I told you before, I knew you a dumb ass Saturday afternoon. It was only a matter of time, that I would get you to prove it to the world.
I think all of us have spent hours talking shit on here. The reason you are mentioning how much time I spent on photoshop, which I don't use, is because you know that you are working harder than me to prove your point. Every one of those images I got from on this board, the bell graph is the only one I edited. So get the fuck outta here with that photoshop.

Once again, you idiot, are working much harder than me. It's hard to prove your ignorance and then defend it at the same time. Ain't it?

 

[mallorquin]

ok you can go back to fingerpainting now son.

and it's spelled negroEs with an 'e' son, practice that with your mom dukes before i get home cause i'm gonna quiz ya right after she cleans my feet makes my dinner and i wax that flat chalky black ass of hers. you can advise her as to these orders of operatin: whether she should take oral before or after she takes it up her ass. can't believe you kiss that brawd in her mouth

Wait we actually make typos? Or was that an "honest mistake"?

Don't have me go back on that NEGRO!

you don't deserve the E.

 

[mallorquin]

and i'm going to go on record to say that this '÷' and '/' this DO mean the same thing

but..

48÷2(9+3)≠(48÷2)(9+3)

I know that I have already brought this up, but for the others who are in here for the first time, this is pretty much all you need to know about Gods_Dumbass. He is finally going on the record. Milestone!



All ya need to know!

 

[tdotlocs]

Do the brackets first son.. math 101... but i had to think about it for second lol

 

[Gods_Debris]

My phone doesn't have the three horizontal lines symbol which; if you've dealt with math at any higher level, then you'd know it means "is defined as"....for the sake of this discussion I'll use double equal signs.

2(a+b )== 2*(a+b) = 2a + 2b


No, I'm making NO presumptions....that's the whole point of the PEMDAS convention being adapted centuries ago. Before being accepted what you're doing was just fine, HOWEVER, since it's adoption, you must follow the the convention.

Y'all added this distributive property angle to try to cloud your way into making the answer 2. Fact is, the distributive property is an alegbraic tool needed to carry variables.
You just solve in arithmetic, no need to distribute (you can distribute, mind you, but you keep butchering the interpretation), so just let the convention guide you through.

i'd like to see the rule or convention that states that the priority of parentheses is locked to the terms inside of its boundries because the only way to solve the problem the way you
have is to ignore orders of operations since you are agreeing that the 2 CAN act independently on the 9 & 3 as you have just shown in you r 'a' plus 'b' example above. the convention is parentheses first but it doesn't state what operation comes first inside or out, in ANY text you or any other person has shown and i'm earnestly asking to see the evidence so i can have the right answer at the end of the day.

there is only one set of rules that say which operations come first that i have seen on display here and it states multiplication before addition whenever possible. P.E.M.D.A.S.

by the way you use the word variable one might be led to believe that a number is NOT a variable which is patently false observation of the definition based on what, i don't know???

 

[Gods_Debris]

I know that I have already brought this up, but for the others who are in here for the first time, this is pretty much all you need to know about Gods_Dumbass. He is finally going on the record. Milestone!



All ya need to know!

you out of breathing class already? have your mom call me when you guys need to be picked up from the bus terminal and in the meantime don't hurt yourself kiddo

 

[LordSinister]

 

[Gods_Debris]

Rawness, you do realize that numbers constitute variables and because algebra is a basic math it's rules are some of the cornerstones that permiate every other branch of mathematics


edit: from the wiki page on Algebraics
Algebra is the branch of mathematics concerning the study of the rules of operations and relations, and the constructions and concepts arising from them, including terms, polynomials, equations and algebraic structures. Together with geometry, analysis, topology, combinatorics, and number theory, algebra is one of the main branches of pure mathematics.


variables can be DEFINED or UNDEFINED but every math problem you've ever seen deals with variables.

1+1=2

are the definite variables one and one being summed

 

[Temujin]

i'd like to see the rule or convention that states that the priority of parentheses is locked to the terms inside of its boundries because the only way to solve the problem the way you
have is to ignore orders of operations since you are agreeing that the 2 CAN act independently on the 9 & 3 as you have just shown in you r 'a' plus 'b' example above. the convention is parentheses first but it doesn't state what operation comes first inside or out, in ANY text you or any other person has shown and i'm earnestly asking to see the evidence so i can have the right answer at the end of the day.

there is only one set of rules that say which operations come first that i have seen on display here and it states multiplication before addition whenever possible. P.E.M.D.A.S.

Did you just imply that the priority of parenthesis is not locked by the terms inside it's boundaries. lol. Damn you were better off with the / meant a fraction argument at least that had mathematical backing you just decided out of no where you are going to include terms outside the parenthesis as part of the parenthesis. WOW

 

[Rawness]

i'd like to see the rule or convention that states that the priority of parentheses is locked to the terms inside of its boundries

I could prove it, but first, do you admit that

ab=a*b

Where a and b are scalars?

 

[Les W]

So the answer to your question is 0.5.

0.5 = 1/2

That is NOT the reciprocal of the original problem, that is the recipricol of 48/(2(9+3)). So you've wasted your time.

and see THAT'S where your wrong ...

if a/b = c then b/a = 1/c

so if 48÷2(9+3) = 288

then 2(9+3)÷48 should be equal to 1/288 and not 1/2 ...

otherwise show me the reciprocal of 48÷2(9+3) !!!

this is common sense ... cats is just ego get in the way of logic right now

 

[Rawness]

0.5 = 1/2



and THAT'S where your wrong ...

if a/b = c then b/a = 1/c

so if 48÷2(9+3) = 288

then 2(9+3)÷48 should be equal to 1/288 and not 1/2 ...

otherwise show me the reciprocal of 48÷2(9+3) !!!

this is common sense

No. I've already told what that was the reciprocal of:

48/(2(9+3))

Which is NOT the same as

48/2(9+3)

 

[Gods_Debris]

Did you just imply that the priority of parenthesis is not locked by the terms inside it's boundaries. lol. Damn you were better off with the / meant a fraction argument at least that had mathematical backing you just decided out of no where you are going to include terms outside the parenthesis as part of the parenthesis. WOW

the parenthetical argument is part and parcel to the fractional argument. it's why they are GROUPED together and this is expounding as to WHY the problem is fractured at the '÷' term.

so again, what's your argument against my first statement?

 

[Les W]

No. I've already told what that was the reciprocal of:

48/(2(9+3))

Which is NOT the same as

48/2(9+3)

Read it again i am asking you to show me the reciprocal of 48÷2(9+3) =
the jig is up fam

 

[Gods_Debris]

I could prove it, but first, do you admit that

ab=a*b

Where a and b are scalars?

certainly... ok i'm following go on


lmao, i answered yes and then had to go look up scalars because i started thinking about vectors and coordinates and hadn't used the term in so long i didn't realize it meant real numbers. i was in a panic after i hit submit for about 30 seconds. thought i had walked into a trap

 

[Rawness]

Read it again i am asking you to show me the reciprocal of 48÷2(9+3) =
the jig is up fam

2/(48(9+3))

What's so hard about that?

Apparently you don't understand what's being argued in here.

 

[Gods_Debris]

2/(48(9+3))

what's that about?

that is contrary to your position fam

 

[Rawness]

certainly... ok i'm following go on


lmao, i answered yes and then had to go look up scalars because i started thinking about vectors and coordinates and hadn't used the term in so long i didn't realize it meant real numbers. i was in a panic after i hit submit for about 30 seconds. thought i had walked into a trap

Nah, not trying to trick you. Had to make that distinction, tho before someone came in here talumbout dot products and cross products to distract...

Do you agree that for ANY function of a, b, c,... (scalars, I'll call them constants from now on) you can add parentheses around each individual constant with out changing the value of the equation?

.i.e. 48/2(9+3) could become (48)/(2)((9)+(3))

Without changing the answer at all.

 

[LordSinister]

2/(48(9+3))

What's so hard about that?

Apparently you don't understand what's being argued in here.

Are you shure you didn't just arrange that to prove your point? Doesn't look right to me........., but I'm just a regular guy.

 

[Rawness]

what's that about?

that is contrary to your position fam

No it's not. Break a piece of paper and you can see it for yourself.

 

[wiZe]

and i'm going to go on record to say that this '÷' and '/' this DO mean the same thing

but..

48÷2(9+3)≠(48÷2)(9+3)

No backing out of your idiocy now. @ you going on record. So now you're saying the almighty Mathway.com is wrong?

Nathan and followup might boot you off the short bus.

 

[Rawness]

Are you shure you didn't just arrange that to prove your point? Doesn't look right to me........., but I'm just a regular guy.

No, I've maintained from the beginning that 48/2(9+3) =

48
_____ * (9+3)
2

Now take the reciprocal of that.

They're trying to say it equals

48
_
2(9+3)

Which is false

 

[Gods_Debris]

No backing out of your idiocy now. @ you going on record. So now you're saying the almighty Mathway.com is wrong?

Nathan and followup might boot you off the short bus.

you dumb giddy bitch, i said they both meant to divide from jump. it can be confirmed by performing a simple search of my responses in this thread. if you chose not to search then by all means please continue to spout even MORE erroneous bullshit

 

[mallorquin]

i didn't look at all of the examples but i know that the first one definitely had a '+' sign in the midst of the equation what I have been saying all along should constitue a 'reset' as much as i was led to believe.

solve this?

48^1 / 2^1(9+3)^1

follow the order of operations. Parentheses? well okay let's do parentheses first because TECHNICALLY you multiply the parentheses first. but it doesn't DO ANYTHING to the problem. it literally MEANS keep this the same. you basically have entered a null value that is always there in the 'real' world of mathematics, so what?

48^1 / 2^1(9+3)

okay we KNOW we can shortcut the order of operations alr
eady because you have entered null values but let's continue and do the next value okay well order of operations says pedmas well... the term outside of the (9+3) value is 2^1 . 2^1 is equal to 2. giving me 2(9+3) under the divding sign.

48^1 / 2(9+3)

the bottom value is then multiplied by distribution. pemdas MULTIPLICATION GET'S PRECENDENCE DAR DAR!!!! you can't combine the two terms until you multiply the 2 through the equation. so what you can combine like terms 9 and 3? if you CAN multiply first then you HAVE TO MULTIPLY FIRST because multiplication supercedes addition in all cases where they converge!

48^1/(18+6)

parentheses get's precendence and the simplification is 24. pemdas

48^1/(24)

the TERM on the other side of the divding sign is 48^1 unto itself SEPERATE of all things dealing with this equation so it must be simplified before it can be addressed in the equation because it is TIED to the exponent ^1.

48/24....

I knew you didn't read the shit. You are using a bunch of words here, that you have no idea about their meaning. Let's start off with the small word, "shortcut". How the fuck, is adding the 9 to the 3 first, a shortcut? You deliberately saying that this is not right to do shows you don't know the first step of the order of operations.

Explain your reasoning for using "Null Value" in your discussion. Google that shit futhafucka and see if it means what you thought it meant.

Do the same shit for converge.

"CAN YOU EXPLAIN HOW THE EXAMPLES POSTED BY tre2k4 ARE DIFFERENT FROM THE ORIGINAL PROBLEM?"

This is not the answer to the question posted by tre2k4. Your reading comprehension is off. Take another look .

no if you look closely it is the "ambiguity" of the ORIGINAL PROBLEM debunked.

answer is TWO by ORDER OF OPERATIONS! you cannot add 9 and 3 before you multiiply.


stop cheating math! lol... shortcuts cost you everytime.

Gonna throw some asterisks below this one to point it out later. **************************************************

how are ya'll adding 9 and 3 before you multiply though?

if the parentheses tell you to multiply whatever they touch and we know parentheses get priority then why are you denying that that is the step that would come first? multiply through THEN add those two terms thus ELIMINATING THE PARENTHESES.

when else do you ADD BUT KEEP THE ADDITION SIGN HANGING AROUND? you have to eliminate all cases of parentheses from the equation first and that means starting over P.E.M.D.A.S. for each case of parentheses until they are all eliminated.


no ambiguity about these points....

Parentheses

Exponent

Multiplication

Division

Addition

Subtraction




when did 2(2+x) stop being 2x+2 ?

edit:

oh shit my bad i was thinking of squaring that equation for a minute. i almost added an x squared term too

Because this is hard work hu?




Gonna throw some asterisks below this one to point it out later. **************************************************

eh, honest mistake doesn't invalidate my point.

whenever you are given a choice between multiplication and addition you multiply smart ass. just because you know 9 and 3 make 12 doesn't mean you can add them because you can ALSO mutliply a 2 through the equation. so now what do excuse do you have for multiplying 24 times 12?

You are the honest mistake.

...

as i said before MOST calculators do not perform order of operations correctly


a problem written like this

48/2(12) is different from 48/2(9+3) and that is the problem or the misunderstanding you are having. where one is ambiguous and the other is not. you are not following order of operations as we have been saying all along

just think about it dude ORDER OF OPERATIONS. follow the STEPS! so you're telling me that you CAN'T multiply the 2 through that equation (9+3)? if you can you must first. sure i can shortcut and add 9 and 3 and get 12 then multiply by 2 as in this case

2(9+3)=..................2(9+3)=
18+6=....................2(12)=
24............................24

but you are not following the order of operations to do it the second way becuase if are following POSSIBLE steps you must MULTIPLY first. like i said. you're cheating.

Pointing out now
**************************************************

the fact that the parentheses ENCLOSE the operation has nothing to do with your extrapolated presumtion that it only acts on numbers inwardly at the onset of solving the equation. i see your problem now. you're caught in a mental loop - a prison based on the shape of the symbol and how it's shape is described but you're ignoring it's mathematical potential which is to distribute through by multiplication. and if you have the choice of adding or multiplying what do you do first? parentheses actually mean if you want to get technical FOCUS HERE first. and it tells you which values to focus on by closing the loop.

Bingo you dumbass, which is why your stupid ass should understand that adding the 9 and the 3 is not a shortcut, but FOCUSING on what is in the parenthesis.
You can't make dumbness up this bad.

because math is a LANGUAGE and some of these niggas act like bitches when you point out that they are reading it wrong, but i say that with absolute objectivity.

(5+3)^2 solved without taking shortcuts

(5+3)(5+3)= 25+15+15+9= 64

treks example has the problem being solved in this manner

(5+3)^2 = (8)^2=64

----------------------------------------------------------------------------------------------------------
Pause!

How the fuck is this taking a shortcut. Your brain is a shortcut. These are not binomials, they are two integers added together and squared inside of ()'s.

----------------------------------------------------------------------------------------------------------

now, if you agree that there is a binomial there, than you must recall that binomials are solved in this manner when raised to a power. i'll square in my example. the process works the same no matter what power you raise the -nomial.
(a+b)^2 = (a+b)(a+b)= a^2+2ab+b^2
----------------------------------------------------------------------------------------------------------
Pause again,
this formula is useful when you do have binomial, it's useless here.

Do you really think it's the same formula for higher order exponents?

Basically you are saying that like...

(a+b)^2 = (a+b)(a+b)= a^2+2ab+b^2
(a+b)^3 = (a+b)(a+b)= a^3+3ab+b^3
(a+b)^4 = (a+b)(a+b)= a^4+4ab+b^4

It doesn't work like that you ignorant fuck! More like this...

Even still, it's useless information because the 9 and the 3 are just integers. Just add them bitch.
----------------------------------------------------------------------------------------------------------

You see why now? Dummy!



I just added you and the moon!

 

[Rick Spanish]

No, I've maintained from the beginning that 48/2(9+3) =

48
_____ * (9+3)
2

Now take the reciprocal of that.

They're trying to say it equals

48
_
2(9+3)

Which is false

The Order of Operations says its

I cant see how you can follow it, and get anything different..

 

[Rawness]

I could prove it, but first, do you admit that

ab=a*b

Where a and b are scalars?

certainly... ok i'm following go on


lmao, i answered yes and then had to go look up scalars because i started thinking about vectors and coordinates and hadn't used the term in so long i didn't realize it meant real numbers. i was in a panic after i hit submit for about 30 seconds. thought i had walked into a trap

Actually, since you admit this truth, answer this:

a/bc =

1) a/(bc)

Or

2) (a/b) * c

????

 

[LordSinister]

So

48/a(b+c) would equal

48
___ (b+c)
a

Not
48/(ab+ac)
Hmmmmmmmmmmm

Sorry. Typing on my nook

Shit got me pissed

 

[Rick Spanish]

Actually, since you admit this truth, answer this:

a/bc =

1) a/(bc)

Or

2) (a/b) * c

????

1.

The / constitutes a faction which makes a the numerator, and bc the denominator.

 

[wiZe]

you dumb giddy bitch, i said they both meant to divide from jump. it can be confirmed by performing a simple search of my responses in this thread. if you chose not to search then by all means please continue to spout even MORE erroneous bullshit

You do know anyone can simply click on pg. 33 or 34 to see you co-signing that shit? You even hit us with '/thread'.

Gods_Idiot, noone takes you serious in this thread. You're like the Flavor Flav of the short bus crew.

 

[Nobody]

...
still waiting...PEMDAS rules basic math...IF you know how to use it.

***************************
More math lessons for some of you:
62-2(5-1)^2+1=????PEMDAS-->62-2(4)^2+1
Now you apply PEMDAS again. You now have something in parentheses and have to decide if you multiply it by a number first or square it...PEMDAS: exponents take priority over multiplication...
-->62-2(16)+1
PEMDAS-->62-32+1
PEMDAS (NOW you can go left to right because addition and subtraction are on the same order)-->30+1-->31

Thanks.
***************************
*waiting for a 288er to refute this* Thanks.

Follow up, once again you re cherry picking . In the example above you are confusing yourself.

Let me break down this problem and set you straight.

62-2(5-1)^2+1

Simplify the parentheses first

62-2(4)^2+1

Exponents next

62-2(16)+1

Multiplication next. Here is where you are mistakenly comparing it to the OP's problem. You see, you are using this to support your theory that anything involving the parentheses should be solved first - the implicit multiplication. But what you are actually doing is using the basic rule that states MULTIPLICATION takes precedence over addition and subtraction. In this particular problem it's not the implicit multiplication but rather simply multiplication.

You arrive at the correct answer, but you are doing it under a false pretense that you apply to other equations that have another symbol that has equal precedence.

So followup, since you keep talking about waiting for people to address this post, now that I have - DO NOT SKIP OVER MY POST.

Like so many of you are doing in this thread. Cherry Picking posts that help your argument, and ignore anything that significantly hurts your argument. You don't want to see your wrong because you simply don't want to be wrong, not because you believe you are correct.

And once again, provide ANOTHER source, preferably two, that states implicit multiplication takes precedence over both explicit multiplication and division.

 

[mallorquin]

certainly... ok i'm following go on


lmao, i answered yes and then had to go look up scalars because i started thinking about vectors and coordinates and hadn't used the term in so long i didn't realize it meant real numbers. i was in a panic after i hit submit for about 30 seconds. thought i had walked into a trap

Why panic?

Is it really that big of a deal? We already know that you are dumb.



Are the stakes getting higher?

 

[Rawness]

Actually, since you admit this truth, answer this:

a/bc =

1) a/(bc)

Or

2) (a/b) * c

????

1.

The / constitutes a faction which makes a the numerator, and bc the denominator.

Congratulations, Nathan, you've officially proven that you do NOT understand the order of operations convention!

Gods_debris, care to chime in?