Yes, we already explained that you can see more than 50% of the Moon due to lunar librations. And you believe that the Moon, whose cratered surface you can see with the unaided eye, is a ball of plasma?
*** Solar Eclipse Caught On My Satellite Data Feed ***
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Do you see the shit you be referencing?
Yeah. Absolutely. I know enough to know we don't live on a globe. So even a flat earther is wrong as fuck, he's still closer to the truth than yall.
Is what it is.......
We don't have to talk about this shit! If I'm so stupid why do yall show up everyday to engage with a stupid person?
I however, have duly noted the times yall got ghost or changed the subject because you were baffled and had no answers. That's real.
Tex-Mex, of course you can't because the earth is still and motionless.
If a plane is going 500 mph and the earth is going 1000 mph, then no we can't see the rotation. But if the ISS is going 17.5K mph, then we can see the 1000 mph rotation???
I don't yet believe the moon is a ball of plasma, but I'm considering it. I personally think the moon behaves similarly to a solar powered light.
Zoom in on it with your phone camera, that should make it clear it's terrestrial.
No. You're still not seeing the Earth rotate. You're seeing the ISS passing over the earth. Just like in a plane or a car. You look out the window and see things passing as you travel past. Just like you can't see the hour hand of a clock move, but it is moving.
Yeah. Absolutely. I know enough to know we don't live on a globe. So even a flat earther is wrong as fuck, he's still closer to the truth than yall.
Is what it is.......
We don't have to talk about this shit! If I'm so stupid why do yall show up everyday to engage with a stupid person?
I however, have duly noted the times yall got ghost or changed the subject because you were baffled and had no answers. That's real.
Speaking of going ghost. You straight avoided this.
These exist all around the world NO NASA
Proving the Earth is a rotating sphere.
Explain that from a flat earth.
No, you wouldn't be able to see the rotation without a time-lapsed video because 1000 mph translates into a rotational period of 24 hours. 1000 mph seems large given our everyday experience, although we have aircraft that can go much faster than that. The point made earlier is that the hour hand of a watch moves twice as fast as the Earth rotates. I doubt you would consider that fast.
The ISS is in low-Earth orbit and has an orbital period of about 90 minutes. But if you see it once you won't see it again 90 minutes later because the Earth will have rotated about 23 degrees in the interim.
I'm watching this review of yesterday's INFOWARS interview now:
All the shit yall ask me and circle ask me Witsit is addressing here. Mind you, INFOWARS is arguing that the earth is a globe. Alex Jones comes on and argues that it's a globe. So all you guys are taking sides with INFOWARS & ALEX JONES. Just wanted to point that out.
Did you ever bother fact-checking that fast-talking meath head or did you soak up every last drop like a good prison bitch? Because once you slow his shit down and dissect each one of his claims line by line, you'd find out the idiot Witless is.
Here let me do it for you. @28:10 explains him to the tee!
You are so stupid!
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Don't lie on me dawg. I responded to that.
The balls on this guy
This is so astonishingly ignorant, wow.
It's like trying to help a slow child add single digits and he's just not seeing it but to you it's so simple.
The fact that you can't see why this is a dumb question is really the entire reason we have this annual meetup. U O E N O.
That other nigga just crazy.
Did you ever bother fact-checking that fast-talking meath head or did you soak up every last drop like a good prison bitch? Because once you slow his shit down and dissect each one of his claims line by line, you'd find out the idiot Witless is.
Here let me do it for you. @28:10 explains him to the tee!
You are so stupid!
So you think I'm gonna listen to this globehead rando?
He's way too stupid to know there's a difference between angular speed and tangential speed.
Dummy, the earth doesn't fucking spin. You're gonna ask me about time-lapse star photography because of that fake globe rotation like that's gonna shut me up. Crickets from you when I posted a video that debunked THAT bullshit.
Nope, not if you want to stay indoctrinated in your idiot cult! The thing about that video, is everything he says can be collaborated by experimentation, NOTING WITLESS MAKES SCIENTIFIC SENSE, THIS IS WHY I CAN LISTEN TO BOTH SIDES AND YOU WILL ALWAYS BE STUCK AT STUPID!So you think I'm gonna listen to this globehead rando?
Tell me you aren't so stupid to not know that slanted lines such as lines in a parking lot can still be parallel to each other even train tracks that are curving in a turn are still parallel in orientation to each other, but I see they don't teach that to you at idiot academy.
Numerous satellite images of the earth were already posted. You never posted anything of substance to counter that and you never will...Why? because it doesn't exist beyond Fischer Price toys. Posting meth-head looking motherfuckers who claim they can prove Scientists such as Einstein are "wrong" is hilarious but doesn't count, man
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One thing to keep in mind about Flattards is that they refuse to examine any information that falsifies their cult dogma, this is why when an airplane pilot offered to fly a group of fleefs over Antarctica or land there during the 24 hour sun there ( an impossible feat on a flat pizza planet) none of the flerfs dared take on this challenge.
I know some may think I am harsh on them but they are actually as dumb and brain way as we claim.
Even Cashier admits to refusing to examine information that can falsify his religion. Indoctrination at its finest.
I remember trolling the flat earth leaders by pretending to be a Flattard by asking them to conduct a fundraiser so we could go to Antarctica so that we can falsify the notion that the Earth has two axis points of rotation as NASA claims, and every single one of them blocked me. This leads me to believe that anyone this dumb is dumb enough to bang a chick who insist on banging only in the ass with the lights off and no touching the pussy. 
Tell me you aren't so stupid that you tried to use this video to argue that those shadows were parallel and not crepuscular. Tell me you're not so stupid that you are trying to compare painted parallel parking lines to shadows of posts (you dumbass) that surely diverge.
I'm perplexed here, why the fuck do yall care so much that I believe the earth is flat?? Yall have spent almost 10 YEARS arguing with me about this shit. I don't get it. What upsets you so much that the earth is flat? And why do you hold onto these balls for dear life?? Please help me understand. What's your motivation???
Who the fuck are you??
So a swinging ball tells you the earth is spinning but an infrared camera doesn't show you the earth is flat???
yeah.......i hear ya
So a swinging ball tells you the earth is spinning but an infrared camera doesn't show you the earth is flat???
yeah.......i hear ya
Here is the math for the pendulm.
The Foucault Pendulum | ScienceBits
Here, we solve the precession of the plane of oscillation of a pendulum. We do so under the following approximations:
(1) The precession rate of the plane of oscillation is slow compared with the oscillation of the pendulum.
(2) The pendulum oscillates with a small amplitude, such that its motion can be approximated as harmonic (a spring).
The derivation involves mapping the pendulum problem into the mass-on-spring problem in two dimensions, and then solving it in polar coordinates, to obtain the equation describing the precession of the oscillation plane.
Other derivations of the precession rate of Foucault's Pendulum are abundant in the literature, these include for example: (1) A geometric solution. This solution is not too rigorous but it certainly illuminates the physical origin of the precession. (2) Derivation of the precession equation using spherical coordinates. This solution involves ugly mathematics arising from the time derivatives of the spherical coordinate system's unit vectors. (3) A full solution in x-y coordinates, it is formally valid also for fast rotations, but requires the solution of two coupled second order differential equations. (Actually, it is not that valid in fast rotating systems because in systems where Coriolis is as important as the main dynamics of the pendulum, the centrifugal force will tend to be important as well, but in all the derivations mentioned here, the centrifugal force is assumed to be constant, and is therefore eliminated by redefining "g".)
Pendula as 2D springs systems
The equation of motion of a mathematical pendulum without Coriolis can be written as:
dLdt=mℓ2ϑ¨=Ngrav
where L is the angular momentum relative to the oscillation axis and Ngrav=−mgℓsinθ is the force moment. We can work here for the moment with scalars because without Coriolis, the motion of the pendulum is in a plane.
We now perform our first approximation. We assume small angle oscillations. That is, we assume that sinϑ≈ϑ. We find:
mℓϑ¨=−mgϑ.
Instead of ϑ, we can change our variable from ϑ to r=ℓϑ which is the distance from the axis (under the small angle limit. We find:
mr¨=−mgℓr.
In other words, the equations describing the pendulum are equivalent (at the small angle limit) to the motion of a spring, with a spring constant given by keff=mg/ℓ and indeed the oscillation frequency of the pendulum is ω=keff/m−−−−−√=g/l−−−√ as it should.
We are therefore allowed to describe the pendulum as a mass on spring. In general, the plane of the oscillation can have precession, we therefore write the motion of the pendulum as a 2D mass on spring problem:
mr¨=−keffr.
(Without any additional forces, the direction of r remains fixed, but with any non-radial force, such as of Coriolis, it will change).
Adding the Coriolis Effect
The Rotating coordinate system {x,y,z} is non-inertial since Earth is rotating. As a result, a Coriolis force is added when working in this frame of reference.
We now add the Coriolis force. Since the mass cannot exit the plane, the equation is valid on to the horizontal directions:
mr¨=−mgℓr−2mΩ×r˙.
For convenience, we will work with polar coordinates - r and θ. (Note that this angle θ is different from the oscillation angle ϑ). The vector rand its time derivatives in is polar coordinates, are given by:
r=rr^,r˙=drdtrr^+rdr^dt=r˙r^+rθ˙θ^
r¨=r¨r^+r˙dr^dt+r˙θ˙θ^+rθ¨θ^+rθ˙dθ^dt
=(r¨−rθ˙2)r^+(2r˙θ˙+rθ¨)θ^.
Next, we need to write the Earth's rotation vector Ω^ in the polar coordinates we use:
Ω^=Ωsinλz^+Ωcosλcosθr^−Ωcosλsinθθ^.
Note that the last term is with a minus sign, because Ω^ has a component opposite to the direction to which θ grows.
The pendulum and the equivalent spring system in polar coordinates. Once the problem becomes 2D, the oscillations are described by r and θ.
We are now in a position where we can take the θ^component of the equation of motion. It will gives us the dynamics of the oscillating plane, i.e., how its direction evolves with time. The component is:
mrθ¨+2r˙θ˙=−2m(Ω^×r˙)θ
where the last parenthesis implies that we take the θ^ component of the vector product. Note that {θ^,r^,z^} is a right handed system (as can be seen in the figure above). Therefore, the θ^ mcomponent of the product is:
(Ω^×r˙)θ=Ωrr˙z−Ωzr˙r=−Ωr˙sinλ,
after plugging in the expressions for r˙ and Ω^. The equation of motion we find is:
mrθ¨+2r˙θ˙=2mr˙Ωsinλ.
In general, this equation cannot be solved without knowing the time dependence of r. However, luckily for us, this equation can be simplified in the limit where the precession is much slower than the oscillations of the pendulum.
The Slow Precession Approximation
If the angular frequency of the pendulum's oscillations is ω then we typically have that r˙∼ωr. On the other hand, the evolution of the direction of oscillations is given by θ, we expect these variations to be of order a day, the time it takes Earth to complete a revolution, i.e., θ˙∼Ωθ and θ¨∼Ω2θ (note that at the end, we have to verify that our solution is consistent with this assumption!).
Since ω≫Ω then θ¨r is smaller than r˙θ˙ by a factor of ω/Ω (e.g., if the pendulum has a few sec period, and 2π/Ω is of order a day, we are talking about a very small correction, one of 1/10000 that we are neglecting.)
Under this limit, the rθ¨ term is neglected, and the equation we find is (after canceling out 2mr˙):
θ˙=Ωsinλ.
This solution satisfies that θ˙∼Ωθ, thus, our assumption is valid.
The time it takes the pendulum to rotate by π radians (i.e., 180°), after which the pendulum appears to have returned to its original state, is:
Tprec=πθ˙=2πΩ12sinλ=day2sinλ.
In Jerusalem, for example λ≈32∘, it is just under a day. In Paris, it will be shorter.
I'll just consider this place closed. You'll continue to believe what you want, but anyone reading this thread will know the truth.
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So based of your derpy knowledge how do you explain anti crepuscular rays? Oops.
I know think you know because of your indoctrination, but in reality infrared light , like everything in the electromagnetic/light spectrum is affected by refraction, the only difference is it is slightly better at cutting through clouds and some haze. The problem with the "we see too far" inferred claims is that you guys never calculate viewer height or refraction indexes for that day.So a swinging ball tells you the earth is spinning but an infrared camera doesn't show you the earth is flat???
yeah.......i hear ya
But what can we expect from a bunch of idiots cosplaying as scientists.
"IR radiation has the same optical properties as visible light, being capable of reflection, refraction, and forming interference patterns."
If you time lapse a the hour hand of a clock you will see it move. Doesn't work that way with the motionless earth we live on.
Refraction does not raise the horizon and flatten the curve. Stop bullshitting, it's overwhelmingly flat.
